Program 41: Take a year as input and print whether it is a leap year or not [Python]

Solution:

year = int(input("Enter a year: "))

if (year % 4) == 0:
  if (year % 100) == 0:
    if (year % 400) == 0:
      print(f"{year} is a leap year") 
    else:
      print(f"{year} is not a leap year")
  else:
    print(f"{year} is a leap year")
else:
  print(f"{year} is not a leap year")

Output:

Enter a year: 2024
2024 is a leap year

Notebook Example:

Human-Written Content: This article was demonstrated by a human, not AI.

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