3 Ways to find if element is present in a List in Python

If you have a list in Python and you want to search to see if a particular element is present in the list, you can make use of the one of the following three ways,

1. Using the "in" and "not in" operator

list_of_cities = ["NYC", "Tokyo", "Chicago", "Austin", "London"]

if "London" in list_of_cities:
    print(f"London is the list {list_of_cities}")

if "Mumbai" not in list_of_cities:
    print(f"Mumbai is not the list {list_of_cities}")

London is the list ['NYC', 'Tokyo', 'Chicago', 'Austin', 'London']
Mumbai is not the list ['NYC', 'Tokyo', 'Chicago', 'Austin', 'London']

2. Using the index() method

my_list = ["Apple", "Mango", "Banana", "Grapes"]
    index = my_list.index("Mango")
    print("Mango is at index", index)
except ValueError:
    print("Mango is not in the list")

Mango is at index 1

Its better to handle ValueError as if the element you are looking for is not found you get this error.

ValueError                                Traceback (most recent call last)
<ipython-input-42-3b37ee759fe2> in <cell line: 3>()
      1 my_list = ["Apple", "Mango", "Banana", "Grapes"]
----> 3 index = my_list.index("Orange")
      4 print("Mango is at index", index)

ValueError: 'Orange' is not in list

3. Using the count() method

my_list = [24,21,12,45,24,12,45,23]

if my_list.count(10) > 0:
    print("10 is found in my_list")
    print("10 is not found in my_list") 

10 is not found in my_list

Find in List Python using count method
Find in List Python using in and not in operator
Find in List Python using index method

HashTags: #searchAListPython #pythonFindInList #listSearchPython #pythonFindElementInList #pythonFindItemInList


- https://docs.python.org/3/library/array.html?highlight=index#array.array.index
- https://docs.python.org/3/library/array.html?highlight=index#array.array.count

Have Questions? Post them here!