Program in C to display sum of series 1 + 1/2 + 1/3 + 1/4 + .... + 1/n : 1000+ C Programs Code2care

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This program calculates sum of series : 1 + 1/2 + 1/3 + 1/4 + .... + 1/n, where n is the number that user enters.

Logic :


/*
 * 1000+ C programs + tutorials
 *
 * 
 * 68_c_program_to_print_sum_of_series 1 + 1/2 + 1/3 + 1/4 + ... + 1/n .c
 *  
 *  
 *
 *  Created on: Oct 25, 2014
 *  Author: Code2care.org
 */

#include 
//#include 

void main() {


//clrscr();

int i,n;
int sum_of_series = 0;
 
 
   printf("\nC Program to print sum of series 1 + 1/2 + 1/3 + 1/4 + .... + 1/n : \n\n ");
 
   printf("Enter the number n : ");
   scanf("%d",&n);
   
   printf("1 + ");
   for ( i = 1 ; i <= n ; i++ )
   {
      sum_of_series = sum_of_series + i;
      if(n != i)
        printf("1/%d  + ", i);
      else
        printf("1/%d",i);
     
   }
   printf(" = 1/%d",sum_of_series);
   

 //    getch(); 

}

Output :

C Program to print sum of series 1 + 1/2 + 1/3 + 1/4 + .... + 1/n : 

Enter the number n : 1 + 1/1  + 1/2  + 1/3  + 1/4  + 1/5  + 1/6  + 1/7  + 1/8  + 1/9  + 1/10 = 1/55

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68 : C Program to display sum of series 1 + 1/2 + 1/3 + 1/4 + .... + 1/n